Question

A small fan in a closed insulated room releases heat at the rate of 42 watts and pushes the air at the rate of 9 m/s with a mass flow rates of 1.2 kg/s. The room has a heater that produces heat at the rate of 0.30 kJ/s as well as a computer that produces 65 watts. Light bulbs in the room produce up to 125 watts. The room loses 0.32 kJ/s. Calculate the amount of heat maintained in the room.

Answer 1

The refrigerator is removing 300 watts of heat every hour.

Energy can only be changed in form; it cannot be created or destroyed, according to the basic law of thermodynamics. For any system, energy transfer examples include mass crossing the control boundary, external work, or heat transfer across the barrier. These have an impact on the energy reserves of the control volume.

The rate of heat removal from within the refrigerator may be calculated using the formula below thanks to the First Law of Thermodynamics and the definition of a refrigeration cycle.

Rate of heat transfer to the space, measured in watts.

Q=800 W W=500

The refrigerator removes heat at a rate of (800-500) 300 watts per hour.

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