Question

Part 1. determine the molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. show your work.

part 2. describe the temperature and pressure conditions at which the gas behaves like an ideal gas.

Answer 1

1. The molar mass of a 0.314-gram sample of gas having a volume of 1.6L at 287K and 0.92 atm is 0.503g/mol.
2. The temperature and pressure of a gas that behaves like an ideal gas is directly proportional to one another.

How to calculate molar mass?

The molar mass of a substance can be calculated by dividing the mass of the substance by its number of moles.

However, the number of moles can be calculated using the following formula:

PV = nRT

Where;

• P = pressure
• V = volume
• R = gas law constant
• T = temperature
• n = no of moles

0.92 × 1.6 = n × 0.0821 × 287

1.47 = 23.56n

n = 1.47/23.56

n = 0.624moles

Molar mass = 0.314g ÷ 0.624mol

Molar mass = 0.503g/mol

Therefore, the molar mass of a 0.314-gram sample of gas having a volume of 1.6L at 287K and 0.92 atm is 0.503g/mol.

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