Answer:
65 square units
Step-by-step explanation:
The easiest way to calculate the area of the given irregular polygon is to divide the shape into a triangle and a trapezoid (see attached diagram).
Area 1: triangle
[tex]\begin{aligned}\textsf{Area of a triangle} & = \sf \dfrac{1}{2} \times base \times height\\ & = \sf \dfrac{1}{2} \times SU \times height\\& = \sf \dfrac{1}{2} \times 8 \times 4\\& = \sf 16\:\:square\:units\end{aligned}[/tex]
Area 2: trapezoid
[tex]\begin{aligned}\textsf{Area of a trapezoid} & = \sf \dfrac{1}{2} (base_a+base_b) \times height\\& = \sf \dfrac{1}{2}(SU+RQ) \times RS\\& = \sf \dfrac{1}{2} (8+6) \times 7\\ & = \sf \dfrac{1}{2}(14) \times 7\\ & = \sf 7 \times 7\\& = \sf 49\:\:square\:units\end{aligned}[/tex]
Area of the polygon
[tex]\begin{aligned}\textsf{Area of the polygon} & = \textsf{Area of triangle}+\textsf{Area of trapezoid}\\& = \sf 16 + 49\\& = \sf 65\:square\:units \end{aligned}[/tex]
Therefore, the area of the polygon is 65 square units.
Learn more about composite shapes here:
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