Question

Find an equation of the line perpendicular to y = − 7 8 x + 2 and containing the point (14, − 3)

Answer 1

Answer:

$y=\frac{-x}{78} -\frac{220}{78}$

Step-by-step explanation:

Remember to create a line perpendicular to one another the slope has to be the reverse reciprocal of the first line.

Given the current slope is $\frac{-78}{1}$ the new slope would be $\frac{1}{78}$.

To find the line that passes through a point with a given slope we must use point slope form, remember the default equation of point slope form:

$y-y1=m(x-x1)$

Where y1 is the y value of the point, m is the slope, and x1 is the x value of the point.

Lets substitute in our values

$y-(-3)=\frac{-1}{78} (x-14)$

Simplify the equation

$y+3=-\frac{1}{78}\left(x-14\right)\\y+3=\frac{-x}{78}+\frac{14}{78}\\y=\frac{-x}{78}-\frac{220}{78}$