The missing value in the logarithm are as follows:
- log₃ 7 - log₃ 2 = log₃ (7 / 2)
- log₉ 7 + log₉ 4 = log₉ 28
- log₆ 1 / 81 =
- - 4 log₆ 3
How to solve logarithm?
Using logarithm rule,
logₐ b - logₐ c = logₐ (b / c)
logₐ b + logₐ c = logₐ (b × c)
Therefore,
log₃ 7 - log₃ 2 = log₃ (7 / 2)
log₉ 7 + log₉ 4 = log₉ (7 × 4) = log₉ 28
log₆ 1 / 81 = log₆ 81⁻¹ = log₆ 3⁻⁴ = - 4 log₆ 3
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