The parabola represented by this graph has the following equation:
y = -16.67(x + 1)² + 2
The equation of a quadratic function, of vertex (h,k), is given by:
y = a(x - h)² + k
In which a is the leading coefficient.
A downward open parabola rises from (-2.4, 4) to (-1,2), and declines through (0.4, -4) on the coordinate plane, hence the vertex is given by:
(-1,2), hence the coefficients are h = -1 and k = 2, and the equation is:
y = a(x - h)² + k
y = a(x + 1)² + 2
We have that when x = -0.4, y = -4, hence the leading coefficient is found as follows:
y = a(x + 1)² + 2
-4 = a(-0.4 + 1)² + 2
a = -6/0.6²
a = -16.67
Hence the equation is:
y = -16.67(x + 1)² + 2
More can be learned about the equation of a parabola at https://brainly.com/question/24737967
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