Respuesta :

a.  

  • i. The angle for telegraph hill is 17.48⁰
  • ii. The coefficient of static friction has to be no less than 0.315

b.

  • i. The angle for Canton Ave. is 20.3⁰
  • ii. The coefficient of static friction has to be no less than 0.37

c.

  • i.The angle for Bradford Street is 22.3⁰
  • ii.  The coefficient of static friction has to be no less than 0.41

What is a grade?

A grade is the ratio of the vertical rise to horizontal run of a road

What is the coefficient of static friction?

The coefficient of static friction is a number which shows the amount of friction between two surfaces.

a. i. Angle for Telegraph hill

Since grade = rise/run

= tan θ

So, θ = tan⁻¹(grade)

Since grade for Telegraph hill = 31.5%

= 31.5/100

= 0.315

θ = tan⁻¹(grade)

θ = tan⁻¹(0.315)

θ = 17.48⁰

So, the angle for telegraph hill is 17.48⁰

ii. Coefficient of static friction for Telegraph hill

For no sliding the coefficient of static friction, μ ≥ tanθ

≥ tan17.48⁰

≥ 0.315

So, the coefficient of static friction has to be no less than 0.315

b. i. Angle for Canton Ave.

Since grade = rise/run

= tan θ

So, θ = tan⁻¹(grade)

Since grade for Canton Ave. = 37%

= 37/100

= 0.37

θ = tan⁻¹(grade)

θ = tan⁻¹(0.37)

θ = 20.3⁰

So, the angle for Canton Ave. is 20.3⁰

ii. Coefficient of static friction for Canton Ave.

For no sliding the coefficient of static friction, μ ≥ tanθ

≥ tan20.3⁰

≥ 0.37

So, the coefficient of static friction has to be no less than 0.37

C. i. Angle for Bradford Street

Since grade = rise/run

= tan θ

So, θ = tan⁻¹(grade)

Since grade for Bradford Street = 41%

= 41/100

= 0.41

θ = tan⁻¹(grade)

θ = tan⁻¹(0.41)

θ = 22.3⁰

So, the angle for Bradford Street is 22.3⁰

ii. Coefficient of static friction for Bradford Street

For no sliding the coefficient of static friction, μ ≥ tanθ

≥ tan22.3⁰

≥ 0.41

So, the coefficient of static friction has to be no less than 0.41

Learn more about grade of a road here:

https://brainly.com/question/16616666

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