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Listed below are systolic blood pressure measurements​ (in mm​Hg) obtained from the same woman. Find the regression​ equation, letting the right arm blood pressure be the predictor​ (x) variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is 85 mm Hg. Use a significance level of 0.05.

Listed below are systolic blood pressure measurements in mmHg obtained from the same woman Find the regression equation letting the right arm blood pressure be class=

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The regression equation between the variables is y = 1.03x + 62.12 and the blood pressure on the left arm given that the systolic blood pressure in the right arm is 85 mm Hg is 149.67

How to determine the regression equation?

From the table of values, we make use of the following representations:

  • Represent the Right Arm on the x axis
  • Represent the Left Arm on the y axis

Using the above representations, we can now plot our data values on a graphing calculator

From the graphing calculator, we have the following summary:

  • Sum of X = 458
  • Sum of Y = 782
  • Mean X = 91.6
  • Mean Y = 156.4
  • Sum of squares (SSX) = 601.2
  • Sum of products (SP) = 618.8

The regression equation is

y = bx + a

Where

b = SP/SSX = 618.8/601.2 = 1.02927

a = MY - bMX = 156.4 - (1.03*91.6) = 62.11843

This gives

y = 1.03x + 62.12

Hence, the regression equation between the variables is y = 1.03x + 62.12

To predict the blood pressure on the left arm given that the systolic blood pressure in the right arm is 85 mm Hg, we have

y = 1.03 * 85 + 62.12

Evaluate

y = 149.67


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