Question

What is the energy of a photon given that the radiation has a wavelength of 440 nm?

Answer 1

The energy of a photon given that the radiation has a wavelength of 440 nm will be  .045 * $10^{-17}$ J

A photon is the quantum of electromagnetic radiation that describes the particle properties of an electromagnetic wave. The energy of a photon is given by the equation E = hf, where E is energy, h is Planck's constant, and f is frequency.

Forms of electromagnetic radiation like radio waves, light waves or infrared (heat) waves make characteristic patterns as they travel through space. Each wave has a certain shape and length. The distance between peaks (high points) is called wavelength

Energy = h*c / lambda

h= plank's constant =  6.626 * $10^{-34}$ J

c = speed of light = 3 * $10^{8}$ m/s

lambda = wavelength = 440 nm = 440 * $10^{-9}$ m

energy of a photon = 6.626 * $10^{-34}$ * 3 * $10^{8}$ / 440 * $10^{-9}$

                                 = 19.878 * $10^{-26}$ /  440 * $10^{-9}$

                                 = .045 * $10^{-17}$ J

To learn more about wavelength  here

https://brainly.com/question/4112024

#SPJ4