The probability of getting exactly one face card is 0.72.
According to the questions two cards are drawn from a deck.
Since, we know that
Total number of cards in a deck = 52
Total number of face cards = 3 × 4 = 12
So, the number of ways of selecting 2 cards from a deck = [tex]^{52} C_{2}[/tex]
And, the total number of ways of getting exactly one face cards
= [tex]^{12} C_{1} \times ^{40} C_{1}[/tex] + [tex]^{40} C_{1} \times ^{12} C_{1}[/tex]
= 2[tex]^{40} C_{1} \times ^{12} C_{1}[/tex]
Therefore, the probability of getting exactly one face card
= [tex]\frac{2(^{40} C_{1} \times ^{12} C_{1})}{^{52C_{2} } }[/tex]
[tex]= \frac{2(\frac{40 \times 39!}{1!\times 39!} \frac{12\times 11!}{11!}) }{\frac{52\times 51\times 50!}{2!\times50!} }[/tex]
[tex]= \frac{2(40\times 12)}{26\times 51}[/tex]
[tex]=\frac{2\times 480}{1326}[/tex]
= 0.72
Hence, the probability of getting exactly one face card is 0.72.
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