Question

What magnitude net force is required to accelerate a 1200-kg car uniformly from 0 m/s to 27.0 m/s in ?

Answer 1

Magnitude of Net force Required to accelerate a 1200kg car uniformly from 0m/s to 27m/s in 10s is 3240N.

Force can be found out using the relation of Force, mass and acceleration.

The relation of Force, mass and acceleration is as follows:

∴ Force = Mass × Acceleration

⇒ Force = 1200kg × Acceleration

Given:

Mass = 1200kg

Final Velocity = 27m/s

Initial Velocity = 0m/s

time = 10s

Now, to find out the acceleration we can use the first equation of motion:

∴ Final Velocity = Initial Velocity + Acceleration × time                

⇒ 27   = 0 + 10a                  

⇒ a = 2.7m/s²        

Putting acceleration in the above mentioned equation,  

∴ Force = 1200kg × Acceleration

⇒ Force = 1200kg × 2.7

⇒ Force = 3240N

Hence, the net force required to accelerate the car uniformly is 3240N.

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Answer 2

The answer is 3240 N.

Intial velocity $\mathrm{u}=0 \mathrm{~m} / \mathrm{s}$

final velocity $\mathrm{v}=27 \mathrm{~m} / \mathrm{s}$

time $t=10$ sec.

Newton's first equation of motion

$v=u+a t$, here a = acceleration

$\mathrm{so}_{0}=(v-u) / t$

$a=(27.0-0) / 10$

$a=2.7 \mathrm{~m} / \mathrm{sec}^{2}$

Force $F=m a$

Mass $\mathrm{m}=1200 \mathrm{~kg}$

$F=1200 \times 2.7$

$F=3240 N$

What is acceleration?

• Acceleration is the rate at which velocity varies over time, both in terms of speed and direction.
• A point or object travelling in a straight path is accelerated if it accelerates or decelerates.

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