a.
Solution Given:
Slope of the line passing through the point is
m= [tex] \frac{y_2-y_1}{x_2-x_1}=\frac{3-(-5)}{-2-2}=\frac{8}{-4}=-2[/tex]
slope=-2
b.
Solution given:
equation is
2x-5y=-10
2x+10=5y
y=2x/5 +10/5
y=2/5 x +3
comparing above equation with y=mx+c
we get
m=2/5
slope=2/5
c.
Slope of the line passing through the point is
m=[tex] \frac{y_2-y_1}{x_2-x_1}[/tex]
-4=[tex] \frac{1-(-9)}{0-x}[/tex]
-4=10/-x
doing criss cross multiplication
-4*-x=10
4x=10
x=10/4
x=5/2
slope=5/2
d.
we have
equation of line passing through the one point is
[tex] y-y_1=m(x-x_1)[/tex]
y-5=-7(x-(-1))
y=-7(x+1)+5
y=-7x-7+5
y=-7x-2 is a required equation:
