The rate of reaction in SN2 reaction becomes four times when the the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles.
In SN2 reaction, the rate of reaction is depend on the concentration of both reactant.
For SN2 reaction,
r = k[bromoethane] [hydroxide ion]
r = k [CH3CH2Br] [OH]
When the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles then,
r = k 2×[CH3CH2Br] × 2[OH]
r = 4k[CH3CH2Br] [OH]
Thus, we concluded that the rate of reaction in SN2 reaction becomes four times.
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