When hydrochloric acid reacts with magnesium metal, hydro- gen gas and aqueous magnesium chloride are produced. what volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium?

Respuesta :

The volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium is 20 L.

Chemical equation:

Mg + 2HCl -----MgCl2 + H2

Given,

Molar mass of Mg = 24g/mol

Mole = Given mass/ Molar mass

Mole= 3/24

= 0.125 mol

From the given equation we get to know that

Mol ratio of Mg and HCl is 1:2.

Therefore,

mol of HCl = (2/1) × mol of Mg

=2× 0.125

= 0.25

Molarity = m× V

= M/m

= 5/0.25

= 20L

Thus, we find that the volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium is 20 L.

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