Question

A 62.0-kg cheetah accelerates from rest to its top speed of 32.0 m/s. (a) How much net work is required for the cheetah to reach its top speed? (b) One food Calorie equals 4 186 J. How many Calories of net work are required for the cheetah to reach its top speed? ​

Answer 1

The energy that it needs to reach the maximum speed is 7583.4 Cal

What is the work done?

In Physics, we know that the work done is the product of the force and the distance moved. However, work can be converted to energy since the both have the same dimensions. We define energy in physics as the ability or the capacity to do work.

Given these information, we know that the work done in moving the cheetah as it accelerates from the bottom to the top of the mountain is equal to the kinetic energy of the cheetah thus we can write;

W = KE = 1/2 mv^2

W= 0.5 * 62.0-kg * ( 32.0 m/s)^2

W = 31744 J

Given that;

1 calories = 4.186 J

x calories = 31744 J

x = 7583.4 Cal

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