When starting a foot race, a 89 kilogram sprinter exerts an average force of 518 newtons backward on the ground for 0.75 seconds. what is his final speed in meters/second at the end of this action?

Respuesta :

The final speed of the sprinter is 4.8 m/s.

What is newtons second law of motion?

According to the second law, the mass of the item or the net force acting on it both affect how quickly an object accelerates.

An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.

An object's acceleration increases as the amount of force exerted on it does.

A decreasing acceleration is caused by a rise in an object's mass.

Calculation of final velocity;

The sprinter exerts an average force of 518 newtons backward on the ground.

The taken by sprinter is 0.75 sec.

The wight of the sprinter is 89Kg.

According to Newton's second law

Force = mass×acceleration

F  = m×a

a = F/m

a = 518/89

a = 6.4 m/sec²

Now, apply the equation of motion of straight line;

final velocity = initial velocity + acceleration×time

As, the sprinter starts from rest; initial velocity = 0.

Substitute all the values;

final velocity = 0 + 6.4×0.75

                     = 4.8 m/sec

Therefore, the final velocity of sprinter comes out to be 4.8 m/sec.

To know more about Newton’s second law, here

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