The system of equations is -x + y = 4 and -2x + y = 0
How to create the system of linear equations?
To do this, we make use of the following ordered pairs
(4, 8)
The above point represents April 2008.
Let the system of equations be
mx + ny = 4
2mx + ny = 0
Substitute (4, 8) for x and y in the above equations.
4m + 8n = 4
8m + 8n = 0
Subtract both equations
4m - 8m = 4
This gives
-4m = 4
Divide by 4
m = -1
Substitute m = -1 in 8m + 8n = 0
-8 + 8n = 0
This gives
8n = 8
Divide by 8
n = 1
So, the system of equations is -x + y = 4 and -2x + y = 0
The graph of the system of equations
The system of equations is -x + y = 4 and -2x + y = 0
See attachment for the graph of the system of equation
Prove that the solution is (4, 8)
The above is represented in the (a) part of this solution
Verify that the solution is (4, 8)
We have:
-x + y = 4 and -2x + y = 0
Substitute (4, 8) for x and y in the above equations.
-4 + 8 = 4 --- true
-2*4 + 8 = 0 --- true
Both equations are true
Hence, the system of equations have been verified
Read more about system of equations at:
brainly.com/question/14323743
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