Question

Calculate the pOH for the following:
1. [H+] = 1 x 10-12 M


2. [OH-] = 1 x 10-6 M


3. [H+] = 1 x 10-1 M


4. [H+] = 1 x 10-4 M


5. [OH-] = 1 x 10-7 M

Answer 1

The  pOH refers to the negative logarithm of the hydroxide concentration.

What is the pOH?

The term pOH refers to the negative logarithm of the hydroxide concentration. Now we know that there is a relation that states that;

[H+]  [OH-]  = 1 * 10^-14

We shall now apply this relation in each case as follows;

[OH-]  =  1 * 10^-14/1 x 10-12

[OH-]  = 1 * 10^-2

pOH = 2

2. pOH = -log( 1 x 10-6 M) = 6

3.  [OH-]  =  1 * 10^-14/ 1 x 10-1

[OH-]  =  1 * 10^-13

pOH = 13

4.  [OH-]  =  1 * 10^-14/  1 x 10-4

[OH-]  =   1 * 10^-10

pOH = 10

5.  pOH = -log(  1 x 10-7) = 7

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