Heat change at constant volume for the combustion of carbon monoxide = -67.71 Kcal
CO(g) + 1/2O2(g) ⟶ CO2(g)
From the above reaction,
∆ng = nP - nR = 1 - ( 1/2 + 1 )
∆ng = - 1/2
Temperature (T) = 17°C (17+ 273) K = 290K (Given)
Now from first law of thermodynamics,
∆H = ∆E + ∆ng RT
ΔΗ = -67.71 + (-1/2) x 2 x 10^-3 x 290
∆H = -67.71 - 0.29 = -68 Kcal
Hence the heat of reaction at constant pressure will be -68 Kcal
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