Total rate at which electrical energy is dissipated
is 5W
Given:
Resistance = 5 ohm
To Find:
total rate at which electrical energy is dissipated
Solution:
The power dissipated in a resistor can be obtained by Ohm's law as P=VXI, where V = voltage and I = current. So, energy dissipated is given by P x t (time)
P = (I)^2R
Let's assume current given is 1
P = 1 x 5
P = 5 W
So, total rate at which electrical energy is dissipated is 5W
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