The sum of an arithmetic progression with first term of 2 and the common difference of 35 is 2340
Sum of arithmetic sequence
Series are defined as the sum of sequence. The formula for calculating the nth term of an arithmetic sequence is expressed as:
S = n/2[2a+(n-1)d]
where;
n is the number of terms
d is the common difference
a is the first term
Given the following parameters from the question
a -2
d = 35
n = 12
Substitute
S = 12/2[2(2)+(12-1)(35)]
S = 6(4+11(35))
S = 6(5+385)
S = 6(390)
S = 2340
Hence the sum of an arithmetic progression with first term of 2 and the common difference of 35 is 2340
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