Using the normal distribution, the z-scores are given as follows:
a) Z = 2.8.
b) Z = 2.8.
The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Item a:
The parameters are:
[tex]\mu = 15, \sigma = 2.5[/tex]
Hence the z-score is:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{22 - 15}{2.5}[/tex]
Z = 2.8.
Item b:
The parameters are:
[tex]\mu = 38.1, \sigma = 6.35[/tex]
Hence the z-score is:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{55.88 - 38.1}{6.35}[/tex]
Z = 2.8.
More can be learned about the normal distribution at https://brainly.com/question/15181104
#SPJ1