Question

A solution is prepared by dissolving 117 grams of salt (NaCI) in 250 milliliters of water (H_{2}*O) What is the molarity of the solution?

D. 468 M NaCI

C. 8.0 M NaCl

A. 0.47 M NaCI

B. 8 * 10 ^ - 3 * MNaCl

Answer 1

Taking into account the definition of molarity, the molarity on the solution is 8 M.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{L}$.

This case

In this case, you know that:

• number of moles= 117 gramsx$\frac{1 mole}{58.45 grams}$=  2 moles, where 58.45$\frac{g}{mole}$ is the molar mass of NaCl.
• volume= 250 mL= 0.250 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{2 moles}{0.250 L}$

Solving:

Molarity= 8 $\frac{moles}{L}$= 8 M

Finally, the molarity on the solution is 8 M.

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