Answer:
Possible values:
0 and 12
Explanation:
To solve the system of equations, let's set y = x^2 - 4x + 3 and y = x - 1 equal to each other to first solve for x.
x^2 - 4x + 3 = x - 1 (add one to both sides)
x^2 - 4x + 4 = x (subtract x from both sides)
x^2 - 5x + 4 = 0
Next, we simply factor the expression. -1 and -4 add up to -5 and multiply to 4, so the factored expression looks like this:
(x - 1)(x - 4) = 0
x = 1 and x = 4 are both solutions to the factored equation. Now, let's plug the values back in to both equations.
(1)^2 - 4(1) + 3 = 0
(4)^2 - 4(4) + 3 = 3
(1) - 1 = 0
(4) - 1 = 3
When 1 is plugged into either equation, 0 is the value of y. For 4, 3 is the value of y. The possible values of product of x and y are below:
0 * 1 = 0
4 * 3 = 12
Brainliest, please :)
