Question

HELP PLEASE. Hector built a tent shaped like a rectangular pyramid. The volume of the tent is 56 cubic ft. The area of the base of the tent is 24 square ft. What is the hieght of Hectors tent in feet?

Answer 1

The height of the rectangular pyramid is 7 ft.

How to get the height of the rectangular pyramid?

First, we know that the volume of a rectangular pyramid is given by:

$V = B*H/3$

Where B is the base, H is the height.

First, we know that the volume is 56 ft³, and the base is 24ft², then we can replace these two in the volume equation to get:

$56 ft^3 = 24ft^2*H/3$

Solving that for H, we get:

$H = 3*(56ft^3/24ft^2) = 7ft$

The height of the rectangular pyramid is 7 ft.

If you want to learn more about rectangular pyramids:

https://brainly.com/question/22328884

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