Using it's concept, the approximate perimeter of pentagon ABCDE is given as follows:
34.4 units.
The perimeter of a figure is given by the sum of the lengths of it's outside dimensions.
In this problem, the vertices are in a coordinate-plane, hence the distances are found using the formula for the distance between two points.
Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
The length of segment AB is:
[tex]AB = \sqrt{(6 - 0)^2+(0 - 7)^2} = 9.2[/tex]
The length of segment BC is:
[tex]BC = \sqrt{(6 - 3)^2+(0 + 4)^2} = 5[/tex]
The length of segment CD is:
[tex]CD = \sqrt{(-3 -3)^2+(-4 + 4)^2} = 6[/tex]
The length of segment DE is:
[tex]DE = \sqrt{(-6 + 3)^2+(0 + 4)^2} = 5[/tex]
The length of segment EA is:
[tex]EA = \sqrt{(-6 +0)^2+(0 - 7)^2} = 9.2[/tex]
Hence the perimeter is:
P = AB + BC + CD + DE + EA = 9.2 + 5 + 6 + 5 + 9.2 = 34.4 units.
More can be learned about the perimeter of a figure at https://brainly.com/question/18610622
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