Question

Suppose a bicyclist rides at a constant velocity of 4.4 m/s up a 10° slope. the total mass of bicycle and rider is 85 kg. neglecting air friction, what is his power output?

Answer 1

Power output will be  = 637.7448 W

Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.

Power Output means the average rate of electric energy delivery during one Metering

The upward force by which the bicycle is riding up will be equal and opposite to m*g*sin(10°) (using newtons third law)

Force (upward ) =  m*g*sin(10°)

given

v = 4.4 m/s

mass (m) = 85 kg

F (upward ) =  m*g*sin(10°)

ma =  m*g*sin(10°)

a = g*sin(10°)

  = 9.8 * sin(10°)  = 1.7052 m / $s^{2}$

Power = work / time = Force . displacement / time = mass * acceleration * velocity

           = m * a * v

           = 85 * 1.7052 * 4.4

           = 637.7448 W

To learn more about Newton's third law  here

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