Question

A coin is placed next to the convex side of a thin spherical glass shell having a radius of curvature of 17.0 cm. Reflection from the surface of the shell forms an image of the 1.5-cm-tall coin that is 6.50 cm behind the glass shell.
a) Where is the coin located?
b) Determine the size of the image.

Answer 1

(a) The position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

(b) The size of the image is 1.8.

Position of the coin

The position of the coin placed next to the convex side of a thin spherical glass shell is calculated as follows;

1/d = 1/f - 1/d'

where;

• d' is the position of the coin's image
• d position of the coin
• f is focal length

Focal length = r/2 = 17 cm / 2 = 8.5 cm

1/d = 1/8.5 - (-1/6.5)

1/d = 1/8.5 + 1/6.5

1/d = 0.1176 + 0.1538

1/d = 0.2714

d = 1/0.2714

d = 3.68 cm

Size of the image

Magnification, M = d'/d

M = (6.5)/(3.68)

M = 1.8

Thus, the position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

The size of the image is 1.8.

Learn more about magnification here: https://brainly.com/question/1599771

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