Question

How deep under the surface of a lake would the pressure be double that at the surface? (1 atm = 1.01 x 105 pa)

Answer 1

At depth of  h = 10.31 m  the surface of a lake would the pressure be double that at the surface

Liquid pressure is the increase in pressure at increasing depths in a liquid. This pressure increases because the liquid at lower depths has to support all of the water above it.

We calculate liquid pressure using the equation liquid pressure = density x acceleration due to g  x depth in fluid.

At the surface of the lake , pressure Po is = 1.01 * $10^{5}$  Pa

to find = depth under the surface of a lake would the pressure be double that at the surface

Pressure under the surface will be = 2 *  1.01 * $10^{5}$  Pa = 2.02 *  $10^{5}$  Pa

Pressure under the surface = Po + ( rho * g * h )

                    2.02 *  $10^{5}$        = 1.01 * $10^{5}$   + (1000 * 9.8 * h)

                     1.01 * $10^{5}$   = 1000 * 9.8 * h

                     h = 10.31 m

At depth of  h = 10.31 m  the surface of a lake would the pressure be double that at the surface

To learn more about liquid pressure here

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