We have proven that ΔACO ≅ ΔBDO using the SAS (Side-angle-side) theorem
Congruent triangles
From the question, we are to prove that ΔACO ≅ ΔBDO
From one of the congruent triangles theorem, we have that
If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.
This is the SAS (Side-angle-side) theorem.
From the given information,
AB and CD intersect at point O
Thus, AO = BO
Also,
∠ACO ≅ ∠BDO
In the diagram, we can as well observe that CO ≅ DO
Thus, we can conclude that AC ≅ BD
Since sides AC, CO and the included angle ACO are congruent to sides BD, DO and the included angle BDO, we can conclude that ΔACO ≅ ΔBDO using the SAS theorem.
Hence, we have proven that ΔACO ≅ ΔBDO
Learn more on Congruent triangles here: https://brainly.com/question/2938476
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