Question

A 1.4 kg bicycle tire with a radius of 33 cm rotates with an angular speed of 155 rpm. Find the angular momentum(L) of the tire, assuming it can be modeled as a hoop.

Answer 1

The angular momentum of the tire is 0.394KGm^2/s.

To find the answer, we have to know more about the angular momentum.

How to find the angular momentum?

• We have the expression for angular momentum as,

                             $L=mvr$

where, m is mass of th body, v is the linear velocity and r is the radius of the circular orbit.

• It is given that,

                 $m=1.4kg\\r=33*10^{-2}m\\w=155rpm=2.58rps$

• Thus, the linear velocity will be,

                   $v=rw=33*10^{-2}*2.58=0.85m/s$

• Then, the angular momentum, L will be,

                  $L=mvr=1.4*0.85*33*10^{-2}=0.394Kgm^2/s$

Thus, we can conclude that, the angular momentum of the tire is 0.394KGm^2/s.

Learn more about the  angular momentum here:

https://brainly.com/question/27750449

#SPJ1