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The mass, in grams, of the chlorine gas will be 0.84 grams

Mass of gases at STP

At standard temperature and pressure, 22.4 L of gas has 1 mole of the gas in it.

This time, what we have is 265 mL of the gas at STP. 265 ml is equivalent to: 265/1000 = 0.265 L

If.

22.4 L = 1 mole

Then,

0.265 L = 0.265 x 1/22.4 = 0.01183 moles

This means that 0.01183 moles of chlorine is present in the gas at STP.

Mass of 0.01183 moles of chlorine = moles x molar mass.

The molar mass of chlorine gas is 71

Mass of the chlorine gas = 0.01183 x 71 = 0.84 grams

More on gases at STP can be found here: https://brainly.com/question/14004233

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