Question

A car starts from rest and constantly accelerates at a rate of 10 [m/s2 ] during a 402 [m] race. how fast is the car going at the finish line?

Answer 1

A car starts from rest and constantly accelerates at a rate of 10 [m/s2 ] during a 402 [m] race. At the finish line, the speed of the car is $\mathbf{89}.\mathbf{6660}\ \mathbit{m}/\mathbit{s}$.

The initial velocity of the car $u = 0$

Constant acceleration $a = 10~ m/s^2$

Distance of the Race $d = 402~ m$

The car is accelerating with a constant acceleration $a$ , so the car's velocity will change with time as it approaches the finish point which is at a distance $d$ from the initial point.

Newton's equation is the backbone of Classical Mechanics. Let's say the velocity of the car at the finish line is $v$.  We know that displacement is the product of average velocity and time.

Or  $s=\frac{u+v}{2}\times t$

Using Newton’s first equation $v\ =\ u\ +\ at$

Newton's equation of motion turns out to be,

$v^2 = u^2+2ad$

$v^2 = 2\times 10 \times 402$

so, $v = \sqrt{8040} = 89.6667 ~m/s$

For more about Newton’s equation of motion, visit: https://brainly.com/question/25951773