Question

How many atoms in 56.4 g of platinum (Pt)

Answer 1

56.4 g of platinum will contain 1.7417 x  $10^{23}$ atoms

Number of atoms in substances

According to Avogadro, 1 mole of any substance contains 6.022 x $10^{23}$ atoms of the substance.

The problem is we don't know how many moles of platinum that are present in 56.4 g. Thus, the first thing is to calculate the number of moles of platinum present in 56.4 g of the substance.

This can be achieved by using the formula, mole = mass/molar mass. Keep in mind that the molar weight of platinum is 195 g/mol.

Therefore,

Mole of 56.4 g of platinum = 56.4/195 = 0.2892 moles

If,

1 mole of any substance = 6.022 x $10^{23}$ atoms

Then,

0.2892 moles of platinum = 0.2892 x 6.022 x $10^{23}$ atoms = 1.7417 x  $10^{23}$ atoms

In other words, 56.4 g of platinum will contain 1.7417 x  $10^{23}$ atoms 1.7417 x  $10^{23}$ atoms of the metal.

More on the number of atoms in substances can be found here: https://brainly.com/question/11373631

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