The resulting solution made from the combination of 50 ml of 1.0 M LiOH with 50 ml of 1.0 M HBr will be identical in all respects to 100 ml of 0.5 M LiBr.
Molarity (M) is defined as the number of moles of solutes dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I unit of Molarity is molar (M) or mol/L.
It is expressed as:
Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume (in L)}}[/tex]
Number of moles = Molarity × Volume
Moles of LiOH = 1.0 × 0.05 [1 ml = 0.001 L]
= 0.05 mol
Moles of HBr = 1.0 × 0.05 [1 ml = 0.001 L]
= 0.05 mol
Now put the values in above formula we get
Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume (in L)}}[/tex]
= [tex]\frac{0.05}{0.1}[/tex]
= 0.5 M LiBr
Thus from the above conclusion we can say that The resulting solution made from the combination of 50 ml of 1.0 M LiOH with 50 ml of 1.0 M HBr will be identical in all respects to 100 ml of 0.5 M LiBr.
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