Answer:
[tex]\huge\boxed{\sf a_{400}=1276}[/tex]
Step-by-step explanation:
79, 82, 85, 88, ....
[tex]a_n=a_1+(n-1)d[/tex]
Where,
Put the givens in the above formula
[tex]a_{400}=79 +(400-1)3\\\\a_{400}=79 + 399\times3\\\\a_{400}=79+ 1197\\\\a_{400}=1276\\\\\rule[225]{225}{2}[/tex]