With the aid of the attached diagrams in the question, we have;
1- Linear relation
2- W = 8•P + 80
3- Please find attached the graph created using a graphing calculator.
4- a) The initial value is the mass of the vase
b) The slope is the mass of each pebble
5- The initial value is lesser than 80
6- 1.2 kilograms
7- 53 pebbles
8- a)
b) (0, 80)
c) The masses are the same
9- Trapezoid area, A = 14•x² - 4•x
10- Tanya and Leah are 18 and 6 years old respectively
How can the table and diagram be analyzed?
1- The relationship between two variables (x and y) is linear if the difference between the terms of the x-values and the terms of the y-values are both constant.
From the table we have;
- The difference between consecutive terms of the x-values is constant and equal to 10
- The difference between consecutive terms of the y-values is constant and equal to 80
The relationship between the x and y-values in the table is therefore;
2. The slope, m, of the linear function is found as follows;
m = (360 - 280)/(30 - 20) = 8
The equation is therefore;
W - 360 = 8•(P - 30)
W = 8•P - 240 + 360 = 8•P + 80
- The equation is; W = 8•P + 80
3. Please find attached the graph drawn with a graphing calculator.
4. The initial value is the output variable (W-value) when the input variable (P-value) is zero.
Therefore;
y = 8×0 + 80 = 80
a) The initial value indicates when the input, P-value is zero, which gives the mass of the vases
b) The slope indicates the number of times an additional pebble increases the weight of the vase and pebble, which is the mass of one pebble
5- A styrofoam cup is lighter than a glass cup, therefore, the initial value, which is the constant term, c, reduces.
- The change is that, the initial value reduces and becomes less than 80
6- The weight, W, of 112 pebbles is therefore;
W = 10 × 112 + 80 = 1,200
- The weight of 112 pebbles is 1,200 g, which is 1.2 kg.
7- 504 = 8•P + 80
Which gives;
504 - 80 = 8•P
P = 424 ÷ 8 = 53
- The number of pebbles in the vase when it weighs 504 g. is 53 pebbles
8- Wilma's equation is; W = 10•P + 80
a) Please find the second graph showing the graphs of the two equations combined.
b) The point of intersection is given by the relation 10•P + 80 = 8•P + 80
2•P = 0
P = 0
Therefore, at the point of intersection, W = 80
The coordinates of the point of intersection is therefore;
c) The point of intersection means that the weight of Wilma's vase and the vase in question 1 are the same.
9. The area of the trapezoid, A, can be expressed as follows;
A = 4•x × ((2•x + 5)+(5•x - 7))/2
A = 2•x × (7•x - 2) = 14•x² - 4•x
- Area of the trapezoid = 14•x² - 4•x
10. Let T represent Tanya's age now and let L represent Leah's current age, we have;
T = L + 12
T - 3 = (L - 3) × 5
Solving gives;
L + 12 - 3 = (L - 3) × 5 (Substitution property)
L + 9 = 5•L - 15
4•L = 9 + 15 = 24
L = 24 ÷ 4 = 6
- Leah's age now, L = 6 years
T = L + 12
Therefore;
T = 6 + 12 = 18
- Tanya's age now, T = 18 years
Learn more about writing equations here:
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