Answer:
LK = 4[tex]\sqrt{2}[/tex]
Step-by-step explanation:
given point J (4, 4 )
then LJ = 4 and JK = 4
using Pythagoras' identity in right triangle LJK
LK² = LJ² + JK² = 4² + 4² = 16 + 16 = 32 ( take square root of both sides )
LK = [tex]\sqrt{32}[/tex] = [tex]\sqrt{16(2)}[/tex] = [tex]\sqrt{16}[/tex] × [tex]\sqrt{2}[/tex] = 4[tex]\sqrt{2}[/tex]
