Answer:
d(t)=-10t-520
Step-by-step explanation:
First you have to find the gradient (m) using the formula [tex]m=\frac{d(t)2-d(t)1}{t2-t1}[/tex]
using the two points you have been given: 1(3,-550) and 2(8,-600)
so you substitute these points into the equation [tex]m=\frac{-600+500}{8-3}[/tex]
m=-10
Now that you have found the m-value you need to find the b-value by using one of the points you already have, I will use Point 2 (8,-600), and substitute it into the equation and solve
d(t)=-10t+b
-600=-10*8+b
-600=-80+b
-520=b
Therefore, the equation is d(t)=-10t-520