A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 35°C is 42.2 torr, what is the volume of the gas sample at standard pressure?

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msm555

Answer:

The volume of the gas sample at standard pressure is 819.5ml

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

[tex] V_1=250ml[/tex]

[tex] V_2=?[/tex]

[tex] P_{total}=735 mmhg[/tex]

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

[tex] P_{water}=42.2mmhg[/tex]

[tex] T_1=35°C=35+273=308 K[/tex]

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

[tex] P_{gas}=P_{total}-P_{water} [/tex]

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

[tex]\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}[/tex]

[tex]V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1[/tex]

[tex]V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1[/tex]

Here [tex]P_2 \:and\: T_2[/tex] are standard pressure and temperature respectively.

we have

[tex]P_2=750mmhg \:and\: T_2=273K[/tex]

Substituting value, we get

[tex]V_2=\frac{692.8}{750}*\frac{273}{308} *250[/tex]

[tex]V_2= 819.51 ml[/tex]

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