Respuesta :
The possible values of X for this game are 0, 1, 2, 3, 4.......n, where n ≥ 1
How to determine the values of X?
From the complete question, we understand that Mr. A wants to plays the game until he wins
This means that
He might win at the first game and he might win after n attempts
So, the values of X are
X = 0, 1, 2, 3, 4.......n
Hence, the possible values of X for this game are 0, 1, 2, 3, 4.......n, where n ≥ 1
The probability that X = n
The probability of x is represented as:
P(x) = nCx * p^x * (1 - p)^(n-x)
So, the probability that X = n is:
P(n) = nCn * p^n * (1 - p)^(n - n)
Evaluate the exponent
P(n) = nCn * p^n * 1
Evaluate the combination expression
P(n) = 1 * p^n * 1
This gives
P(n) = p^n
Hence, the probability that X = n is p^n
Prove that it satisfies the PMF conditions.
The distribution satisfies PMF conditions because
- The sum of the probabilities is 1
- No probability is negative
- Each probability value is between 0 and 1 (inclusive)
Calculate E(X)
The expected value E(x) is calculated using
E(x) = n * p
So, we have:
E(x) = np
Hence, the value of E(x) is np
Calculate V(X)
The variance V(x) is calculated using
V(x) = √n * p * (1 - p)
So, we have:
V(x) = √np(1 - p)
Hence, the value of V(x) is √np(1 - p)
Study the memoryless property of X.
The memoryless property of X is that each probability of X is independent
Read more about probability at:
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