The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.
Question 1: a³ - 1000b³
a³ - b³
= (a-b) × (a² +ab +b²)
So,
(a - 10b) × (a² + 10ab + 100b²)
Question 2: 64a³ - 125b³
a³ - b³
= (a-b) × (a² +ab +b²)
So,
(4a - 5b) • (16a² + 20ab + 25b²)
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