The vertical and horizontal component of the maximum displacement are 0.15m and 0.85m.
What is the velocity of the pendulum just after the collision?
As per conversation of momentum, mass of bullet × velocity= mass of pendulum × velocity
=> 0.029kg × 200 = 3.429 × velocity of pendulum
=> Velocity of pendulum= 5.8/3.429 = 1.7 m/s
What is the amplitude of the pendulum's motion?
- As per conversation of energy,
1/2 × mass of pendulum × velocity²=1/2 × k × amplitude²
- Here, k = mg/L = (3.429×9.8)/2.5 = 13.44 N/m
- So, 3.429×1.7²= 13.44× amplitude²
=> 10 = 13.44× amplitude²
=> Amplitude = √(10/13.44)
= 0.86m
What is the angle made by the pendulum with vertical direction at largest displacement?
Angle = tan inverse (amplitude/length of pendulum)
= tan inverse (0.86/2.5)
= 20°
What is the maximum displacement along vertical direction?
Maximum displacement along vertical direction= L - L×cos20°
= 2.5 - 2.5×cos20°
= 0.15 m
What's the maximum displacement along horizontal direction?
Maximum displacement along horizontal direction= Lsin20°
= 2.5 × sin 20°
= 0.85m
Thus, we can conclude that the vertical and horizontal component of the maximum displacement are 0.15m and 0.85m.
Learn more about the pendulum motion here:
brainly.com/question/15261645
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