The inverse function of f(x) = 4^(x + 3) -2 is f-1(x) = log₄(x + 2) - 3
How to determine the inverse function?
The function is given as:
f(x) = 4^(x + 3) -2
Rewrite as:
y = 4^(x + 3) -2
Swap x and y
x = 4^(y + 3) -2
Add 2 to both sides
x + 2 = 4^(y + 3) -2 + 2
This gives
x + 2 = 4^(y + 3)
Take the logarithm of both sides
log(x + 2)= log(4)^(y + 3)
Apply the base rule of logarithm
log(x + 2)= (y + 3)log(4)
Divide both sides by log(4)
log(x + 2)/log(4) = y + 3
Apply the change of base rule of logarithm
log₄(x + 2) = y + 3
Subtract 3 from both sides
log₄(x + 2) - 3 = y + 3 - 3
Evaluate the difference
log₄(x + 2) - 3 = y
Rewrite as:
y = log₄(x + 2) - 3
Rewrite as:
f-1(x) = log₄(x + 2) - 3
Hence, the inverse function of f(x) = 4^(x + 3) -2 is f-1(x) = log₄(x + 2) - 3
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