The domain of the rational function is:
{x ∈ ℝ| x ≠ –2, 2}
Here we have the rational function:
[tex]f(x) = \frac{x^2 - x - 12}{x^3 - 4x^2 - 4x + 16}[/tex]
We want to get the domain of that function. First, we can rewrite the numerator and denominator as:
[tex]x^2 -x - 12 = (x + 3)*(x - 4)[/tex]
[tex]x^3 - 4x^2 - 4x + 16 = (x - 4)*(x + 2)*(x - 2)[/tex]
Then we can rewrite the rational function as:
[tex]f(x) = \frac{(x + 3)*(x - 4)}{(x - 4)*(x + 2)*(x - 2)}[/tex]
This can be simplified to:
[tex]f(x) = \frac{(x + 3)}{(x + 2)*(x - 2)}[/tex]
Now, the domain will be the set of all real numbers, minus the values of x that generate problems.
In this case, the values:
x = -2 and x = 2 make the denominator to be zero, and we can't divide by zero, so we conclue that the domain is:
{x ∈ ℝ| x ≠ –2, 2}
If you want to learn more about rational functions:
https://brainly.com/question/1851758
#SPJ1