Question

Which equation is equivalent to
f(x) = 16x4 -81 = 0?
✓(4x² +9)(4x² - 9) = 0 ✓
COMPLETE
Select all of the zeroes of the function.
O
2/3
DONE

Answer 1

The given equation is equivalent to (4x²+9)*(4x²-9) or (4x²+9)*(2x-3)*(2x+3). And the zero of the function are: $\pm \frac{3}{2}$ and $\pm \frac{3}{2}i$.

What is a Quadratic Function?

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

For solving a quadratic function you should find the discriminant: D=b²-4ac and after that use this variable in the formula: $x=\frac{-b\pm\sqrt{D} }{2a}$.

Factoring

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

The question gives: $16x^4-81=0$, you can factor this equation. See below.

(4x²+9)*(4x²-9)

(4x²+9)*(2x-3)*(2x+3)

Therefore, you should choose one of options: (4x²+9)*(4x²-9) or (4x²+9)*(2x-3)*(2x+3).

Next step is to solve the given equation. Solving for  (4x²+9)*(2x-3)*(2x+3)=0, then:

For 2x-3=0

      x=3/2

For 2x+3=0

      x= -3/2

For 4x²+9=0

      4x²=-9

       x²= -9/4

      x = $\pm \sqrt{\frac{-9}{4} }$

      x   =$\pm \frac{3}{2}*\sqrt{-1 }\\ \\ \pm \frac{3}{2}*i$

Read more about complex number here:

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