Question

The sum of five consecutive positive integers is 2020. Find the largets of these numbers.

Answer 1

The largest integers of the numbers is 406.

How to find the five consecutive positive integers?

The sum of five consecutive positive integers is 2020.

Therefore,

let

the first positive integer = x

Hence,

x + x + 1 + x + 2 + x + 3 + x + 4 = 2020

5x + 10 = 2020

5x = 2020 - 10

5x = 2010

x = 2010 / 5

x = 402

largest integer = 402 + 4 = 406

Therefore, the largest integers of the numbers is 406.

learn more on integers here: https://brainly.com/question/15292688?

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