the area of the minor segment is 0. 29 cm^2
From the information given, we have the following parameters;
It is important to note the formula for area of a sector is given as;
Area = πr² + θ/360° - 1/ 2 r² sin θ
The value for π = 3.142
θ = 30°
Now, let's substitute the values
Area = 3. 142 × 5² × 30/ 360 - 1/ 2 × 5² × sin 30
Find the difference
Area = 3. 142 × 25 × 1/ 12 - 1/ 2 × 25 × 1/2
Multiply through
Area = 6. 54 - 6. 25
Area = 0. 29 cm^2
The area of the minor segment is given as 0. 29 cm^2
Thus, the area of the minor segment is 0. 29 cm^2
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