Respuesta :
The kinetic energy is 1.8 × 10^ -1 J.
Rolling items each rotate and have linear (or translational) movement. consequently, they've both linear and rotational kinetic power. since the rotational kinetic strength of a rolling object depends at the inertia of the item.
The only kinetic energy involved here is rotational kinetic energy.
Kinetic Energy (Rotational) = 1/2Iω²
I = Moment of Inertia of a thin hoop =(Mass)(Radius)2
Mass = 3.0 kg
Radius = 10 cm = 0.10 m
ω = angular speed = 3.5 rad/s
Kinetic Energy (Rotational) = 1/2 * 3 * 12.25 J.
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The Kinetic energy is of thin hoop can be found out using the formulas of Rotational Kinetic Energy. The Kinetic Energy of the hoop is 18.375J.
Rolling items rotate and have linear or translational movement. consequently, they have both linear and rotational kinetic power. Since the rotational kinetic strength of a rolling object depends on the Inertia of the item.
The only kinetic energy involved here is Rotational Kinetic Energy.
Rotational Kinetic Energy = 1/2Iω²
where, I = Moment of Inertia of a thin hoop =(Mass)(Radius)²
where, Mass of hoop, m = 3.0 kg
Radius of loop, R = 10 cm = 0.10 m
Angular speed, w= 3.5 rad/s
Since, Rotational Kinetic Energy = 1/2 × 3 × 12.25 J.
Rotational Kinetic Energy = 18.375J
Hence, Rotational Kinetic Energy is 18.375J
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