The ramp does 480J of useful work with an efficiency of 80% .
What is efficiency of work done ?
- Efficiency is the ratio of the useful energy released by a system to the input energy .
- Mathematically, efficiency of energy = out put energy/ input energy
What is the useful work done by the ramp having efficiency 80% and an input work done 600J?
- The efficiency =output work done/ input work done
- 80% =output work done/ 600J
- output work done =( 80×600)/100
=480J
Thus, we can conclude that the useful work done by the ramp is 480J.
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